CALCULATOR
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Estimate ideal transfer duration from decimal gigabytes and megabits per second. Example: Data size (decimal GB): 2 GB decimal, Effective transfer rate (decimal Mbit/s): 100 Mbit/s decimal gives 160 seconds. 1 GB = 10^9 bytes; 1 byte = 8 bits; 1 Mbit/s = 10^6 bit/s. Decimal units only, not GiB/MiB. Constant effective user-supplied rate; protocol overhead, latency and competing traffic excluded, so
1 GB = 10^9 bytes; 1 byte = 8 bits; 1 Mbit/s = 10^6 bit/s. Decimal units only, not GiB/MiB. Constant effective user-supplied rate; protocol overhead, latency and competing traffic excluded, so actual duration can be longer. Derivation: Dimensional cancellation: 10^9 bytes/GB × 8 bits/byte ÷ 10^6 bits/Mbit = 8000 Mbit/GB.
Accepted inputs: Data size (decimal GB): 0 to 1,000,000 GB decimal; Effective transfer rate (decimal Mbit/s): 0.001 to 1,000,000 Mbit/s decimal.
ideal transfer duration from decimal gigabytes and megabits per second
How the calculation works
seconds = size GB × 8000 / rate Mbit/s
Worked example
With data size (decimal gb) 2 GB decimal, effective transfer rate (decimal mbit/s) 100 Mbit/s decimal, ideal transfer duration from decimal gigabytes and megabits per second is 160 seconds.
Assumptions and limits
1 GB = 10^9 bytes; 1 byte = 8 bits; 1 Mbit/s = 10^6 bit/s. Decimal units only, not GiB/MiB. Constant effective user-supplied rate; protocol overhead, latency and competing traffic excluded, so actual duration can be longer. Derivation: Dimensional cancellation: 10^9 bytes/GB × 8 bits/byte ÷ 10^6 bits/Mbit = 8000 Mbit/GB.