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Ideal Catenary Height Above Lowest Point Calculator

Ideal Catenary Height Above Lowest Point. Example: Scale: 2 m, Horizontal offset: 3 m gives 2.70481923049 m. Supplied mathematical scale a, ideal catenary centered at lowest point; height above that point only. No load, tension, material or structural safety model. Only this original stated job is proposed, not full historical source coverage. Input domains and output unit must be visible.

YOUR INPUTS Live calculation

Supplied mathematical scale a, ideal catenary centered at lowest point; height above that point only. No load, tension, material or structural safety model. Only this original stated job is proposed, not full historical source coverage. Input domains and output unit must be visible. Derivation: cosh(u)-1=2sinh²(u/2). With u=x/a and E=expm1(u/2)-expm1(-u/2)=2sinh(u/2), height=(a/2)EE. expm1 preserves tiny exponent differences; opposite-signed expm1 terms are subtracted without cancellation. Existing engine mul reduces left to right: multiply0.5 by scale, then E, then E, rather than squaring E first. This preserves representable subnormal heights that premature squaring could erase.

Accepted inputs: Scale: 1 to 1,000 m; Horizontal offset: -10 to 10 m.

Example values. Enter your own inputs.

Ideal Catenary Height Above Lowest Point

2.70481923m

How the calculation works

height=2a sinh²(x/(2a)); E=expm1(x/(2a))-expm1(-x/(2a)); evaluate (a/2) E E

Worked example

With scale 2 m, horizontal offset 3 m, ideal catenary height above lowest point is 2.70481923 m.

Assumptions and limits

Supplied mathematical scale a, ideal catenary centered at lowest point; height above that point only. No load, tension, material or structural safety model. Only this original stated job is proposed, not full historical source coverage. Input domains and output unit must be visible. Derivation: cosh(u)-1=2sinh²(u/2). With u=x/a and E=expm1(u/2)-expm1(-u/2)=2sinh(u/2), height=(a/2)EE. expm1 preserves tiny exponent differences; opposite-signed expm1 terms are subtracted without cancellation. Existing engine mul reduces left to right: multiply0.5 by scale, then E, then E, rather than squaring E first. This preserves representable subnormal heights that premature squaring could erase.

Ideal Catenary Height Above Lowest Point2.70481923 m
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